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Actual exam question for AACE International's CCP exam Question #: 56 Topic #: 1
An agricultural corporation that paid 53% in income tax wanted to build a grain elevator designed to last twenty-five (25) years at a cost of $80,000 with no salvage value. Annual income generated would be $22,500 and annual expenditures were to be $12,000. Answer the question using a straight line depreciation and a 10% interest rate. The following question requires your selection of CCC/CCE Scenario 17 (4.2.50.1.1) from the right side of your split screen, using the drop down menu, to reference during your response/choice of responses. What is the 25 year after tax present worth of this project?
To calculate the 25-year after-tax present worth of this project, we need to consider the income, expenses, depreciation, and taxes. First, calculate the annual depreciation: Depreciation=Initial CostLife=80,00025=3,200\text{Depreciation} = \frac{\text{Initial Cost}}{\text{Life}} = \frac{80,000}{25} = 3,200Depreciation=LifeInitial Cost=2580,000=3,200 Now, calculate the taxable income each year: Taxable Income=Revenue-Expenses-Depreciation=22,500-12,000-3,200=7,300\text{Taxable Income} = \text{Revenue} - \text{Expenses} - \text{Depreciation} = 22,500 - 12,000 - 3,200 = 7,300Taxable Income=Revenue-Expenses-Depreciation=22,500-12,000-3,200=7,300 Calculate the tax: Tax=Taxable Income×Tax Rate=7,300×0.53=3,869\text{Tax} = \text{Taxable Income} \times \text{Tax Rate} = 7,300 \times 0.53 = 3,869Tax=Taxable Income×Tax Rate=7,300×0.53=3,869 Net income after tax: Net Income=Taxable Income-Tax=7,300-3,869=3,431\text{Net Income} = \text{Taxable Income} - \text{Tax} = 7,300 - 3,869 = 3,431Net Income=Taxable Income-Tax=7,300-3,869=3,431 Add back depreciation (since it's a non-cash expense): Cash Flow=3,431+3,200=6,631\text{Cash Flow} = 3,431 + 3,200 = 6,631Cash Flow=3,431+3,200=6,631 Finally, calculate the present worth using the formula for the present worth of an annuity: Present Worth=6,631×(1-(1+0.10)-250.10)≈137,466\text{Present Worth} = 6,631 \times \left(\frac{1-(1+0.10)^{-25}}{0.10}\right) \approx 137,466Present Worth=6,631×(0.101-(1+0.10)-25)≈137,466 So, the correct answer is B. $137,466.
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