Here are all the actual test exam dumps for IT exams. Most people prepare for the actual exams with our test dumps to pass their exams. So it's critical to choose and actual test pdf to succeed.

Exam 312-39 Topic 2 Question 28 Discussion

Actual exam question for EC-COUNCIL's 312-39 exam
Question #: 28
Topic #: 2
Which of the following Windows event is logged every time when a user tries to access the "Registry" key?

Suggested Answer: D Vote an answer

The Windows event that is logged when a user tries to access a "Registry" key is identified by the event ID
4657. This event ID corresponds to the modification of a registry value. Here's how the process is tracked and logged:
* Detection: The system monitors access to registry keys and values.
* Logging: If a user accesses a registry key, and the key's audit policy is set to log such events, the event is logged.
* Event ID 4657: This specific event ID is used to denote that a registry value was modified, which includes creation, modification, and deletion of registry values.
* Audit Policy: For the event to be logged, "Set Value" auditing must be enabled in the registry key's System Access Control List (SACL).
References: The EC-Council SOC Analyst course materials and study guides detail the various Windows event IDs and their significance in monitoring and analyzing security events. Event ID 4657 is specifically covered as part of the curriculum that deals with registry access monitoring and logging1. Additionally, Microsoft's official documentation provides comprehensive information on this event ID and its role in security auditing2.

by Michell at May 27, 2024, 03:01 AM

Comments

Chosen Answer:
This is a voting comment (?) , you can switch to a simple comment.
Switch to a voting comment New
Nick name: Submit Cancel
A voting comment increases the vote count for the chosen answer by one.

Upvoting a comment with a selected answer will also increase the vote count towards that answer by one. So if you see a comment that you already agree with, you can upvote it instead of posting a new comment.